[Homework Home > Conservation_of_Momentum] |
[1] | A cannon, whose mass is M= kg fires a cannon ball in a horizontal direction. The cannon ball has a mass of m= kg and is fired toward the right with a velocity of v= m/s . With what speed does the cannon recoil to the left? |
[2] | A man with a mass of M= kg is riding down the road on a cart that has a mass of m= kg . When he and the cart are going m/s , he suddenly jumps off in such a way that he has zero horizontal velocity. How fast is the cart moving after he jumps off? |
[3] | A car of mass m_{1}= kg is at rest at a traffic light (the car on the right).
Along comes a car (the left car) with mass m_{2}= kg and initial speed v_{2i}= m/s
and hits the car at rest.
There is a big crash, and the two cars end up sticking together after the collision.
What speed does the "big mess of two cars stuck together" have after the collision? |
[4] | Two blocks, one of mass m_{1}= kg and the other of mass m_{2}= kg are attached with a rope, as shown. Between them is a spring compressed by a distance d= meters . The spring has a spring constant k= N/m . Suddenly, the rope breaks, and the spring quickly expands, pushing m_{1} to the left with speed v_{1} and m_{2} to the right with speed v_{2}. What are v_{1} and v_{2}? |
[5] | Two cars, one with mass m_{1}= kg and the other with mass
m_{2}= kg crash in an intersection, as shown here.
Before the crash, car m_{1} was headed East with a speed v_{1i}= m/s and car m_{2} was headed North with a speed v_{2i}= m/s . After the crash, the cars stick together. What is the speed of the 2-car wreck after the collision, and with what angle, \theta, does it leave the crash point? |
[6] | A rubber ball of mass m_{1}= kg is moving to the right with speed v= m/s . It collides elastically with another ball of mass m_{2}= kg , which is sitting at rest. m_{2} is larger than m_{1}. What are the speeds of the balls, v_{1} and v_{2}, after the collision? |
[7] | A block of mass m_{1}= kg is on a curved track, a distance h= m above the ground as shown here. When released, it slides down the track and collides elastically with another block of mass m_{2}= kg , which is sitting at rest. m_{2} is larger than m_{1}. This means that m_{1} will bounce back in the direction from which it came after the collision. How far back up the track will m_{1} bounce after the collision? |
[8] | A bullet with a mass of m_{b}= kg is speeding toward a block of mass m= kg .
The bullet is moving at speed v_{b}= m/s and the block is at rest.
The bullet collides with the block, embeds itself into the block, and knocks the block over the edge. The edge is a height h= m above the ground. How far from the edge does the block m (with the bullet inside) land? |
[9] | Here is a problem dealing with the most general form of an elastic collision (two things collide
and bounce off of each other).
There is one car, call it car #1, moving toward the right. It has an initial speed v_{1i}= m/s , and a mass of m_{1}= kg . There is another car, call it car #2. It can be moving, or not. Enter 0 if you want it at rest. Enter a + speed if you want it moving toward the right, or a - speed if you want it moving toward the left. The speed of car #2 is v_{2i}= m/s and the mass of car #2 is m_{2}= kg . The problem here is to calculate what the speed of each car will be after the collision. |
[10] | A bullet moving with speed v_{b}= m/s hits and embeds itself into a big wooden block of mass M= kg . The bullet has a mass of m_{b}= kg . How far will the block rise after the bullet becomes embedded in it? |