[Homework Home > Currents_and_Magnetic_Fields]

 [1] A particle with a charge of +/-q= C enters a region of magnetic field as shown here, with a speed of v= m/s . The B-field has a strength of B= Tesla . When the particle enters the B-field region, it is seen to sweep out a semi-circle, and hit the edge of the device a distance x= cm to the right of where it entered. Is the charge positive or negative? What is the mass of the charge?

 [2] Two wires, on carrying a current I1= Ampere and the other carrying I2= Ampere are shown. Both currents are in the same direction, into the screen. What is the net B-field at point P? d= m , a= m , and b= m

 [3] Two current carrying wires are shown here. They carry currents in opposite directions, in this case, one out of the computer screen and the other into the screen. I1= Amperes , I2= Amperes . The wires are a distance d= meters apart. What is the B-field at a distance x= meters from the left wire?

 [4] Two current carrying wires are shown here. They carry currents in the same direction, in this case, out of the computer screen. I1= Amperes , I2= Amperes . The wires are a distance d= meters apart. What is the B-field at a distance x= meters from the left wire?

 [5] A wire carrying a current I1= A is shown here. Right next to it is a loop of wire carrying a current I2= A . Here, a= m , h= m , and w= m . What net force does the wire exert on the loop?

 [6] A bar of mass m= kg can slide on two bare wires along a horizontal table. A current I= A is maintained in the wires and bar. The whole system is immersed in a vertical, downward magnetic field, as shown. Here, B= Tesla and the length of the bar is L= m . What is the acceleration of the bar? Will it move to the left or right?

 [7] A bar is on an inclined pair of wires, at \theta= degrees as shown here. The bar has a mass of m= kg and slides freely on the wires that are L= m apart. A magnetic field of strength B= Tesla is pointed straight down. What current is needed to run through the system so that the bar does not slide down the incline?